TM 5-3805-258-24-1POWER TRAINNOSPIN DIFFERENTIAL GROUPS Y S T E M S O P E R A T I O NCLUTCH AND HOLDOUT RING6. Driven clutch. 8. Holdout ring. 20. Notch in holdoutring. 21. Cam.OPERATION OF NOSPIN DIFFERENTIALWhen a wheel is made to turn faster than the speedof the bevel gear, the “clutch action” (the stopping ofpower to drive axle) of the NoSpin differential willlet this axle turn faster than the speed of the bevelgear.The “clutch action” of the NoSpin differential isas follows: If spider (17) turns, spider key (19) lo-cates center cam (15) and the spider and the centercam turn at the speed of the bevel gear. The centercam turns holdout ring (8) and cam (21) at the speedof the bevel gear. The spider turns driven clutch (6)at the speed of the bevel gear. The driven clutch turnsthe side gear, axle and wheel at the speed of the bevelgear.When the wheel is made to turn faster than thespeed of the bevel gear, the teeth of center cam (15)work like ramps and the teeth of cam (21) move upthe teeth of the center cam. This action causes drivenclutch (6) to become disengaged (not engaged) withthe spider. The driven clutch pulls holdout ring (8)out of the grooves in the center cam. The frictionbetween the holdout ring and driven clutch turns theholdout ring until notch (20) in the holdout ringengages with spider key (19). The holdout ring is nowturned by the spider key at the speed of the bevelgear. The teeth of the holdout ring are now in aposition so they can not engage the notches in thecenter cam. The driven clutch and cam move aroundthe holdout ring at a speed faster than the speed ofthe bevel gear. The holdout ring keeps the drivenclutch and cam from being engaged (engagement)with the center cam and spider. The driven clutch,cam, axle shaft and wheel now turn freely.The opposite side clutch, cam and holdout ring areheld engaged to the center cam and spider by spring(7) as long as the driven wheel turns slower.When the speed of the wheel that is not engagedbecomes slower and near the speed of the bevel gear,the resistance of the ground to the wheel causes thetorque on this wheel to be in a small reverse direction.This causes the driven clutch and cam to turn in adirection opposite the direction of the bevel gear. Thefriction between the holdout ring and the drivenclutch causes the holdout ring to move in a directionopposite the direction of the bevel gear. Notch (20) inthe holdout ring moves away from spider key (19).When the teeth of the holdout ring are in a position toengage the notches in center cam (15), the force ofthe spring causes the driven clutch and cam to moveto the inside. The driven clutch pushes the holdoutring. The holdout ring now engages the center camand is turned at the speed of the bevel gear. The teethof cam (21) now engage the center cam and the teethof the drive clutch engage the spider. At this time,both wheels are turned at the same speed.NOTE: When both wheels are turned at the samespeed they do not necessarily have equal torque. Forexample: When one wheel starts to turn faster on ice(tends to spin), both clutches engage and both wheelsturn at the same speed. The wheel that is on ice willhave less torque.3-56
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